1/4w-1/3=42/3w=

Solution for 1/4w-1/3=42/3w= equation:

1/4w-1/3=42/3w=

We move all terms to the left:

1/4w-1/3-(42/3w)=0


Domain of the equation: 4w!=0

w!=0/4

w!=0

w∈R



Domain of the equation: 3w)!=0

w!=0/1

w!=0

w∈R


We add all the numbers together, and all the variables

1/4w-(+42/3w)-1/3=0

We get rid of parentheses

1/4w-42/3w-1/3=0

We calculate fractions


(-36w^2)/108w^2+27w/108w^2+(-1512w)/108w^2=0

We multiply all the terms by the denominator


(-36w^2)+27w+(-1512w)=0

We get rid of parentheses

-36w^2+27w-1512w=0

We add all the numbers together, and all the variables

-36w^2-1485w=0

a = -36; b = -1485; c = 0;
Δ = b2-4ac
Δ = -14852-4·(-36)·0
Δ = 2205225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2205225}=1485$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1485)-1485}{2*-36}=\frac{0}{-72}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1485)+1485}{2*-36}=\frac{2970}{-72}
=-41+1/4
$