1/4x+-32=7+4x

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Solution for 1/4x+-32=7+4x equation:



1/4x+-32=7+4x
We move all terms to the left:
1/4x+-32-(7+4x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
We add all the numbers together, and all the variables
1/4x-(4x+7)-32+=0
We add all the numbers together, and all the variables
1/4x-(4x+7)=0
We get rid of parentheses
1/4x-4x-7=0
We multiply all the terms by the denominator
-4x*4x-7*4x+1=0
Wy multiply elements
-16x^2-28x+1=0
a = -16; b = -28; c = +1;
Δ = b2-4ac
Δ = -282-4·(-16)·1
Δ = 848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{848}=\sqrt{16*53}=\sqrt{16}*\sqrt{53}=4\sqrt{53}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{53}}{2*-16}=\frac{28-4\sqrt{53}}{-32} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{53}}{2*-16}=\frac{28+4\sqrt{53}}{-32} $

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