1/4x+1/3x=4

Solution for 1/4x+1/3x=4 equation:

1/4x+1/3x=4

We move all terms to the left:

1/4x+1/3x-(4)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We calculate fractions


3x/12x^2+4x/12x^2-4=0

We multiply all the terms by the denominator


3x+4x-4*12x^2=0

We add all the numbers together, and all the variables

7x-4*12x^2=0

Wy multiply elements

-48x^2+7x=0

a = -48; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-48)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-48}=\frac{-14}{-96}
=7/48
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-48}=\frac{0}{-96}
=0
$