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1/4x+1/5=3(2/3x+1)
We move all terms to the left:
1/4x+1/5-(3(2/3x+1))=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x+1))!=0We calculate fractions
x∈R
(-(3(2*4x*5)/12x^2+36x^2/12x^2+3x/12x^2=0
We can not solve this equation
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