1/4x+1/6x=48

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Solution for 1/4x+1/6x=48 equation:



1/4x+1/6x=48
We move all terms to the left:
1/4x+1/6x-(48)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
We calculate fractions
6x/24x^2+4x/24x^2-48=0
We multiply all the terms by the denominator
6x+4x-48*24x^2=0
We add all the numbers together, and all the variables
10x-48*24x^2=0
Wy multiply elements
-1152x^2+10x=0
a = -1152; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1152)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-1152}=\frac{-20}{-2304} =5/576 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-1152}=\frac{0}{-2304} =0 $

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