1/4x+17=x=4

Solution for 1/4x+17=x=4 equation:

1/4x+17=x=4

We move all terms to the left:

1/4x+17-(x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

-1x+1/4x+17=0

We multiply all the terms by the denominator


-1x*4x+17*4x+1=0

Wy multiply elements

-4x^2+68x+1=0

a = -4; b = 68; c = +1;
Δ = b2-4ac
Δ = 682-4·(-4)·1
Δ = 4640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4640}=\sqrt{16*290}=\sqrt{16}*\sqrt{290}=4\sqrt{290}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-4\sqrt{290}}{2*-4}=\frac{-68-4\sqrt{290}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+4\sqrt{290}}{2*-4}=\frac{-68+4\sqrt{290}}{-8}
$