1/4x+18=3/4(2x=5)

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Solution for 1/4x+18=3/4(2x=5) equation: 



1/4x+18=3/4(2x=5)

We move all terms to the left:

1/4x+18-(3/4(2x)=0



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R





Domain of the equation: 42x+18!=0

We move all terms containing x to the left, all other terms to the right

42x!=-18

x!=-18/42

x!=-3/7

x∈R



We calculate fractions


(42x+18)/(168x^2+18)+(-(3*4x)/(168x^2+18)=0



We calculate terms in parentheses: +(-(3*4x)/(168x^2+18), so:

-(3*4x)/(168x^2+18

We add all the numbers together, and all the variables

-(+3*4x)/(168x^2+18

We multiply all the terms by the denominator


-(+3*4x)

We get rid of parentheses

-3*4x

Wy multiply elements

-12x

Back to the equation:

+(-12x)



We get rid of parentheses

(42x+18)/(168x^2+18)-12x=0

We multiply all the terms by the denominator


(42x+18)-12x*(168x^2+18)=0

We multiply parentheses

-2016x^3+(42x+18)-216x=0

We get rid of parentheses

-2016x^3+42x-216x+18=0

We do not support expression: x^3

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