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1/4x+2/3x+7=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
3x/12x^2+8x/12x^2+7=0
We multiply all the terms by the denominator
3x+8x+7*12x^2=0
We add all the numbers together, and all the variables
11x+7*12x^2=0
Wy multiply elements
84x^2+11x=0
a = 84; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·84·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*84}=\frac{-22}{168} =-11/84 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*84}=\frac{0}{168} =0 $
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