1/4x+20=-1/2x-4

Solution for 1/4x+20=-1/2x-4 equation:

1/4x+20=-1/2x-4

We move all terms to the left:

1/4x+20-(-1/2x-4)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x-4)!=0

x∈R


We get rid of parentheses

1/4x+1/2x+4+20=0

We calculate fractions


2x/8x^2+4x/8x^2+4+20=0

We add all the numbers together, and all the variables

2x/8x^2+4x/8x^2+24=0

We multiply all the terms by the denominator


2x+4x+24*8x^2=0

We add all the numbers together, and all the variables

6x+24*8x^2=0

Wy multiply elements

192x^2+6x=0

a = 192; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·192·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*192}=\frac{-12}{384}
=-1/32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*192}=\frac{0}{384}
=0
$