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1/4x+24=x
We move all terms to the left:
1/4x+24-(x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-1x+1/4x+24=0
We multiply all the terms by the denominator
-1x*4x+24*4x+1=0
Wy multiply elements
-4x^2+96x+1=0
a = -4; b = 96; c = +1;
Δ = b2-4ac
Δ = 962-4·(-4)·1
Δ = 9232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9232}=\sqrt{16*577}=\sqrt{16}*\sqrt{577}=4\sqrt{577}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-4\sqrt{577}}{2*-4}=\frac{-96-4\sqrt{577}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+4\sqrt{577}}{2*-4}=\frac{-96+4\sqrt{577}}{-8} $
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