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1/4x+3/2x=7/8
We move all terms to the left:
1/4x+3/2x-(7/8)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/4x+3/2x-(+7/8)=0
We get rid of parentheses
1/4x+3/2x-7/8=0
We calculate fractions
(-112x^2)/512x^2+128x/512x^2+768x/512x^2=0
We multiply all the terms by the denominator
(-112x^2)+128x+768x=0
We add all the numbers together, and all the variables
(-112x^2)+896x=0
We get rid of parentheses
-112x^2+896x=0
a = -112; b = 896; c = 0;
Δ = b2-4ac
Δ = 8962-4·(-112)·0
Δ = 802816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{802816}=896$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(896)-896}{2*-112}=\frac{-1792}{-224} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(896)+896}{2*-112}=\frac{0}{-224} =0 $
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