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1/4x+3/5x=272
We move all terms to the left:
1/4x+3/5x-(272)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
5x/20x^2+12x/20x^2-272=0
We multiply all the terms by the denominator
5x+12x-272*20x^2=0
We add all the numbers together, and all the variables
17x-272*20x^2=0
Wy multiply elements
-5440x^2+17x=0
a = -5440; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-5440)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-5440}=\frac{-34}{-10880} =1/320 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-5440}=\frac{0}{-10880} =0 $
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