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1/4x+32=-2x+4
We move all terms to the left:
1/4x+32-(-2x+4)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
1/4x+2x-4+32=0
We multiply all the terms by the denominator
2x*4x-4*4x+32*4x+1=0
Wy multiply elements
8x^2-16x+128x+1=0
We add all the numbers together, and all the variables
8x^2+112x+1=0
a = 8; b = 112; c = +1;
Δ = b2-4ac
Δ = 1122-4·8·1
Δ = 12512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12512}=\sqrt{16*782}=\sqrt{16}*\sqrt{782}=4\sqrt{782}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-4\sqrt{782}}{2*8}=\frac{-112-4\sqrt{782}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+4\sqrt{782}}{2*8}=\frac{-112+4\sqrt{782}}{16} $
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