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1/4x+3x-5=5/4(x-4)
We move all terms to the left:
1/4x+3x-5-(5/4(x-4))=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 4(x-4))!=0We add all the numbers together, and all the variables
x∈R
3x+1/4x-(5/4(x-4))-5=0
We calculate fractions
3x+(4xx/(16x^2x+(-(5*4x)/(16x^2x-5=0
We can not solve this equation
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