1/4x+8=x=2

Solution for 1/4x+8=x=2 equation:

1/4x+8=x=2

We move all terms to the left:

1/4x+8-(x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

-1x+1/4x+8=0

We multiply all the terms by the denominator


-1x*4x+8*4x+1=0

Wy multiply elements

-4x^2+32x+1=0

a = -4; b = 32; c = +1;
Δ = b2-4ac
Δ = 322-4·(-4)·1
Δ = 1040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1040}=\sqrt{16*65}=\sqrt{16}*\sqrt{65}=4\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-4\sqrt{65}}{2*-4}=\frac{-32-4\sqrt{65}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+4\sqrt{65}}{2*-4}=\frac{-32+4\sqrt{65}}{-8}
$