1/4x-(x+1/3)=1/12(x+3)

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Solution for 1/4x-(x+1/3)=1/12(x+3) equation: 


x in (-oo:+oo)

(1/4)*x-x-(1/3) = (1/12)*(x+3) // - (1/12)*(x+3)

(1/4)*x-((1/12)*(x+3))-x-(1/3) = 0

(-1/12)*(x+3)+(1/4)*x-x-1/3 = 0

x/4-1/12*(x+3)-x-1/3 = 0

(-1/12*3*4*(x+3))/(3*4)+(3*x)/(3*4)+(3*4*(-x))/(3*4)+(-1*4)/(3*4) = 0

3*x-1/12*3*4*(x+3)+3*4*(-x)-1*4 = 0

2*x-12*x-4-3 = 0

-10*x-4-3 = 0

-10*x-7 = 0

(-10*x-7)/(3*4) = 0

(-10*x-7)/(3*4) = 0 // * 3*4

-10*x-7 = 0

-10*x-7 = 0 // + 7

-10*x = 7 // : -10

x = 7/(-10)

x = -7/10

x = -7/10

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