1/4x-(x-3)=2

Solution for 1/4x-(x-3)=2 equation:

1/4x-(x-3)=2

We move all terms to the left:

1/4x-(x-3)-(2)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We get rid of parentheses

1/4x-x+3-2=0

We multiply all the terms by the denominator


-x*4x+3*4x-2*4x+1=0

Wy multiply elements

-4x^2+12x-8x+1=0

We add all the numbers together, and all the variables

-4x^2+4x+1=0

a = -4; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·(-4)·1
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{2}}{2*-4}=\frac{-4-4\sqrt{2}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{2}}{2*-4}=\frac{-4+4\sqrt{2}}{-8}
$