1/4x-1/5x=6

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Solution for 1/4x-1/5x=6 equation:



1/4x-1/5x=6
We move all terms to the left:
1/4x-1/5x-(6)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
We calculate fractions
5x/20x^2+(-4x)/20x^2-6=0
We multiply all the terms by the denominator
5x+(-4x)-6*20x^2=0
Wy multiply elements
-120x^2+5x+(-4x)=0
We get rid of parentheses
-120x^2+5x-4x=0
We add all the numbers together, and all the variables
-120x^2+x=0
a = -120; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-120)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-120}=\frac{-2}{-240} =1/120 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-120}=\frac{0}{-240} =0 $

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