If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/4x-13/12=1-1/6x
We move all terms to the left:
1/4x-13/12-(1-1/6x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/4x-(-1/6x+1)-13/12=0
We get rid of parentheses
1/4x+1/6x-1-13/12=0
We calculate fractions
(-1872x^2)/288x^2+72x/288x^2+48x/288x^2-1=0
We multiply all the terms by the denominator
(-1872x^2)+72x+48x-1*288x^2=0
We add all the numbers together, and all the variables
(-1872x^2)+120x-1*288x^2=0
Wy multiply elements
(-1872x^2)-288x^2+120x=0
We get rid of parentheses
-1872x^2-288x^2+120x=0
We add all the numbers together, and all the variables
-2160x^2+120x=0
a = -2160; b = 120; c = 0;
Δ = b2-4ac
Δ = 1202-4·(-2160)·0
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-120}{2*-2160}=\frac{-240}{-4320} =1/18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+120}{2*-2160}=\frac{0}{-4320} =0 $
| 8(2-8x)=-40-8x | | 4X-4(5x+14)=56 | | -8(-5v-3)=8(-1+3v) | | 6x-7/5=-8+x/4 | | -165+4x=209-13x | | 68*23=x | | 2x+25=3x-36 | | f(×)=7-4× | | 8/x=10/35 | | Y=-4x+6;x=1 | | -7/9(x+13)=14 | | 12-4n=-3-1n | | .8(m+12)=8 | | x/10-3=7/20 | | Y=1.9x+1.4 | | 3a+21=7-41 | | 5x-4+3x=8x-4 | | 0.5(5-7x)=8+(4x+6) | | 92=-4X+6(5x-15) | | 6n-4=6n-4 | | 12x*4=7x-21 | | 50-3=2x | | 2/3x+3=1/4x−7 | | 2m-7=25 | | 2x+3(x-5=130 | | 7(7-6i)-2(2+8i)=0 | | t+4/-2+12=8 | | 3x^2-11=6x+13 | | 2x-(x-2)=7x-4(2*x) | | 18(1.2)^(2x-1)=900 | | (x+52)+(2x-20)+(x)=180 | | u/5+5.1=-7.4 |