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1/4x-2=6+5/2x
We move all terms to the left:
1/4x-2-(6+5/2x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/4x-(5/2x+6)-2=0
We get rid of parentheses
1/4x-5/2x-6-2=0
We calculate fractions
2x/8x^2+(-20x)/8x^2-6-2=0
We add all the numbers together, and all the variables
2x/8x^2+(-20x)/8x^2-8=0
We multiply all the terms by the denominator
2x+(-20x)-8*8x^2=0
Wy multiply elements
-64x^2+2x+(-20x)=0
We get rid of parentheses
-64x^2+2x-20x=0
We add all the numbers together, and all the variables
-64x^2-18x=0
a = -64; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·(-64)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*-64}=\frac{0}{-128} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*-64}=\frac{36}{-128} =-9/32 $
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