1/4x-40=x-10

Solution for 1/4x-40=x-10 equation:

1/4x-40=x-10

We move all terms to the left:

1/4x-40-(x-10)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We get rid of parentheses

1/4x-x+10-40=0

We multiply all the terms by the denominator


-x*4x+10*4x-40*4x+1=0

Wy multiply elements

-4x^2+40x-160x+1=0

We add all the numbers together, and all the variables

-4x^2-120x+1=0

a = -4; b = -120; c = +1;
Δ = b2-4ac
Δ = -1202-4·(-4)·1
Δ = 14416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14416}=\sqrt{16*901}=\sqrt{16}*\sqrt{901}=4\sqrt{901}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-4\sqrt{901}}{2*-4}=\frac{120-4\sqrt{901}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+4\sqrt{901}}{2*-4}=\frac{120+4\sqrt{901}}{-8}
$