If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/4x-5/6x=7
We move all terms to the left:
1/4x-5/6x-(7)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 6x!=0We calculate fractions
x!=0/6
x!=0
x∈R
6x/24x^2+(-20x)/24x^2-7=0
We multiply all the terms by the denominator
6x+(-20x)-7*24x^2=0
Wy multiply elements
-168x^2+6x+(-20x)=0
We get rid of parentheses
-168x^2+6x-20x=0
We add all the numbers together, and all the variables
-168x^2-14x=0
a = -168; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·(-168)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*-168}=\frac{0}{-336} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*-168}=\frac{28}{-336} =-1/12 $
| n+n+2=98 | | 87+w=2w+11 | | 9x-6-8=2x | | 1.156=(1851-x)/x | | 10+3v=1 | | Y=1/2|x|+5 | | −3(2x−2.5)=−5(3x−1.5)−3(2 | | −3(2x−2.5)=−5(3x−1.5)−3(2 | | −3(2x−2.5)=−5(3x−1.5)−3(2 | | −3(2x−2.5)=−5(3x−1.5)−3(2 | | −3(2x−2.5)=−5(3x−1.5)−3(2 | | −3(2x−2.5)=−5(3x−1.5)−3(2 | | −3(2x−2.5)=−5(3x−1.5)−3(2 | | −3(2x−2.5)=−5(3x−1.5)−3(2 | | x-38+16=34 | | 4.24^x=3.59 | | (A)8x-3-20=7 | | (A)8x^3-20=7 | | 37-6x+2=30-3x | | 36-6x+2=30-3x | | 12x-30-4x-8=14 | | 4-8x-6-2x=0 | | 9x-6-7x-2=0 | | 6x+15-2x-10=51 | | X^2-4+p=0 | | 0.7×x=2.8 | | 7-x=15-3x | | 2h+3=3h-6 | | 6u=6/7 | | -6=6s | | 13x-28=3x+7 | | (x-40)=(x+40) |