1/4x-7/8x=20-35

Solution for 1/4x-7/8x=20-35 equation:

1/4x-7/8x=20-35

We move all terms to the left:

1/4x-7/8x-(20-35)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R


We add all the numbers together, and all the variables

1/4x-7/8x-(-15)=0

We add all the numbers together, and all the variables

1/4x-7/8x+15=0

We calculate fractions


8x/32x^2+(-28x)/32x^2+15=0

We multiply all the terms by the denominator


8x+(-28x)+15*32x^2=0

Wy multiply elements

480x^2+8x+(-28x)=0

We get rid of parentheses

480x^2+8x-28x=0

We add all the numbers together, and all the variables

480x^2-20x=0

a = 480; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·480·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*480}=\frac{0}{960}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*480}=\frac{40}{960}
=1/24
$