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1/4x-8=1/3(x-19)
We move all terms to the left:
1/4x-8-(1/3(x-19))=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3(x-19))!=0We calculate fractions
x∈R
(3xx/(12x^2x+(-(1*4x)/(12x^2x-8=0
We can not solve this equation
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