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1/4x^2=250
We move all terms to the left:
1/4x^2-(250)=0
Domain of the equation: 4x^2!=0We multiply all the terms by the denominator
x^2!=0/4
x^2!=√0
x!=0
x∈R
-250*4x^2+1=0
Wy multiply elements
-1000x^2+1=0
a = -1000; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-1000)·1
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{10}}{2*-1000}=\frac{0-20\sqrt{10}}{-2000} =-\frac{20\sqrt{10}}{-2000} =-\frac{\sqrt{10}}{-100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{10}}{2*-1000}=\frac{0+20\sqrt{10}}{-2000} =\frac{20\sqrt{10}}{-2000} =\frac{\sqrt{10}}{-100} $
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