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1/4x=2/3x-50
We move all terms to the left:
1/4x-(2/3x-50)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x-50)!=0We get rid of parentheses
x∈R
1/4x-2/3x+50=0
We calculate fractions
3x/12x^2+(-8x)/12x^2+50=0
We multiply all the terms by the denominator
3x+(-8x)+50*12x^2=0
Wy multiply elements
600x^2+3x+(-8x)=0
We get rid of parentheses
600x^2+3x-8x=0
We add all the numbers together, and all the variables
600x^2-5x=0
a = 600; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·600·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*600}=\frac{0}{1200} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*600}=\frac{10}{1200} =1/120 $
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