1/4x=20;x=40

Solution for 1/4x=20;x=40 equation:

1/4x=20x=40

We move all terms to the left:

1/4x-(20x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

-20x+1/4x=0

We multiply all the terms by the denominator


-20x*4x+1=0

Wy multiply elements

-80x^2+1=0

a = -80; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-80)·1
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{5}}{2*-80}=\frac{0-8\sqrt{5}}{-160}
=-\frac{8\sqrt{5}}{-160}
=-\frac{\sqrt{5}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{5}}{2*-80}=\frac{0+8\sqrt{5}}{-160}
=\frac{8\sqrt{5}}{-160}
=\frac{\sqrt{5}}{-20}
$