1/4x=x-12

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Solution for 1/4x=x-12 equation:



1/4x=x-12
We move all terms to the left:
1/4x-(x-12)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
We get rid of parentheses
1/4x-x+12=0
We multiply all the terms by the denominator
-x*4x+12*4x+1=0
Wy multiply elements
-4x^2+48x+1=0
a = -4; b = 48; c = +1;
Δ = b2-4ac
Δ = 482-4·(-4)·1
Δ = 2320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2320}=\sqrt{16*145}=\sqrt{16}*\sqrt{145}=4\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-4\sqrt{145}}{2*-4}=\frac{-48-4\sqrt{145}}{-8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+4\sqrt{145}}{2*-4}=\frac{-48+4\sqrt{145}}{-8} $

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