1/4y+1/3y=2-16

Solution for 1/4y+1/3y=2-16 equation:

1/4y+1/3y=2-16

We move all terms to the left:

1/4y+1/3y-(2-16)=0


Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R


We add all the numbers together, and all the variables

1/4y+1/3y-(-14)=0

We add all the numbers together, and all the variables

1/4y+1/3y+14=0

We calculate fractions


3y/12y^2+4y/12y^2+14=0

We multiply all the terms by the denominator


3y+4y+14*12y^2=0

We add all the numbers together, and all the variables

7y+14*12y^2=0

Wy multiply elements

168y^2+7y=0

a = 168; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·168·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*168}=\frac{-14}{336}
=-1/24
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*168}=\frac{0}{336}
=0
$