1/4y+4/5y=y+3

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Solution for 1/4y+4/5y=y+3 equation: 



1/4y+4/5y=y+3

We move all terms to the left:

1/4y+4/5y-(y+3)=0



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R





Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R



We get rid of parentheses

1/4y+4/5y-y-3=0

We calculate fractions


-y+5y/20y^2+16y/20y^2-3=0

We add all the numbers together, and all the variables

-1y+5y/20y^2+16y/20y^2-3=0

We multiply all the terms by the denominator


-1y*20y^2+5y+16y-3*20y^2=0

We add all the numbers together, and all the variables

21y-1y*20y^2-3*20y^2=0

Wy multiply elements

-20y^3-60y^2+21y=0

We do not support eypression: y^3

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