1/4y-(y+2/3)=1/12(y-18)

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Solution for 1/4y-(y+2/3)=1/12(y-18) equation: 


y in (-oo:+oo)

(1/4)*y-y-(2/3) = (1/12)*(y-18) // - (1/12)*(y-18)

(1/4)*y-((1/12)*(y-18))-y-(2/3) = 0

(-1/12)*(y-18)+(1/4)*y-y-2/3 = 0

y/4-1/12*(y-18)-y-2/3 = 0

(-1/12*3*4*(y-18))/(3*4)+(3*y)/(3*4)+(3*4*(-y))/(3*4)+(-2*4)/(3*4) = 0

3*y-1/12*3*4*(y-18)+3*4*(-y)-2*4 = 0

2*y-12*y-8+18 = 0

18-10*y-8 = 0

10-10*y = 0

(10-10*y)/(3*4) = 0

(10-10*y)/(3*4) = 0 // * 3*4

10-10*y = 0

10-10*y = 0 // - 10

-10*y = -10 // : -10

y = -10/(-10)

y = 1

y = 1

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