1/5(-10x+35)-3=32+5x

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Solution for 1/5(-10x+35)-3=32+5x equation: 



1/5(-10x+35)-3=32+5x

We move all terms to the left:

1/5(-10x+35)-3-(32+5x)=0



Domain of the equation: 5(-10x+35)!=0

x∈R



We add all the numbers together, and all the variables

1/5(-10x+35)-(5x+32)-3=0

We get rid of parentheses

1/5(-10x+35)-5x-32-3=0

We multiply all the terms by the denominator


-5x*5(-10x+35)-32*5(-10x+35)-3*5(-10x+35)+1=0

Wy multiply elements

-25x^2(--160x(--15x(-+1=0

We use the square of the difference formula

-25x^2(+160x(+15x(-1=0

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