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(1/5)*(9*x-12) = (3/10)*(6*x-8) // - (3/10)*(6*x-8)
(1/5)*(9*x-12)-((3/10)*(6*x-8)) = 0
(1/5)*(9*x-12)+(-3/10)*(6*x-8) = 0
1/5*(9*x-12)-3/10*(6*x-8) = 0
1/5*(9*x-12)-3/10*(6*x-8) = 0
0 = 0
0 = 0
x belongs to the empty set
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