1/5(-20k+55)=3+12k

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Solution for 1/5(-20k+55)=3+12k equation: 



1/5(-20k+55)=3+12k

We move all terms to the left:

1/5(-20k+55)-(3+12k)=0



Domain of the equation: 5(-20k+55)!=0

k∈R



We add all the numbers together, and all the variables

1/5(-20k+55)-(12k+3)=0

We get rid of parentheses

1/5(-20k+55)-12k-3=0

We multiply all the terms by the denominator


-12k*5(-20k+55)-3*5(-20k+55)+1=0

Wy multiply elements

-60k^2(--15k(-+1=0

We use the square of the difference formula

-60k^2(+15k(-1=0

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