1/5(-20k+70)=3+12k

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Solution for 1/5(-20k+70)=3+12k equation: 



1/5(-20k+70)=3+12k

We move all terms to the left:

1/5(-20k+70)-(3+12k)=0



Domain of the equation: 5(-20k+70)!=0

k∈R



We add all the numbers together, and all the variables

1/5(-20k+70)-(12k+3)=0

We get rid of parentheses

1/5(-20k+70)-12k-3=0

We multiply all the terms by the denominator


-12k*5(-20k+70)-3*5(-20k+70)+1=0

Wy multiply elements

-60k^2(--15k(-+1=0

We use the square of the difference formula

-60k^2(+15k(-1=0

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