1/5(-25+15a)=1/2(6a-10)

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Solution for 1/5(-25+15a)=1/2(6a-10) equation: 


a in (-oo:+oo)

(1/5)*(15*a-25) = (1/2)*(6*a-10) // - (1/2)*(6*a-10)

(1/5)*(15*a-25)-((1/2)*(6*a-10)) = 0

(1/5)*(15*a-25)+(-1/2)*(6*a-10) = 0

1/5*(15*a-25)-1/2*(6*a-10) = 0

1/5*(15*a-25)-1/2*(6*a-10) = 0

0 = 0

0 = 0

a belongs to the empty set

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