1/5(-2x-7)+7=8

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Solution for 1/5(-2x-7)+7=8 equation: 



1/5(-2x-7)+7=8

We move all terms to the left:

1/5(-2x-7)+7-(8)=0



Domain of the equation: 5(-2x-7)!=0

x∈R



We add all the numbers together, and all the variables

1/5(-2x-7)-1=0

We multiply all the terms by the denominator


-1*5(-2x-7)+1=0

Wy multiply elements

-5x(-+1=0

We use the square of the difference formula

-5x(-1=0

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