1/5(-a+4)=6(2a+3)

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Solution for 1/5(-a+4)=6(2a+3) equation: 



1/5(-a+4)=6(2a+3)

We move all terms to the left:

1/5(-a+4)-(6(2a+3))=0



Domain of the equation: 5(-a+4)!=0

a∈R



We add all the numbers together, and all the variables

1/5(-1a+4)-(6(2a+3))=0

We multiply all the terms by the denominator


-((6(2a+3)))*5(-1a+4)+1=0



We calculate terms in parentheses: -((6(2a+3)))*5(-1a+4), so:

(6(2a+3)))*5(-1a+4

We add all the numbers together, and all the variables

-1a+(6(2a+3)))*5(+4

Back to the equation:

-(-1a+(6(2a+3)))*5(+4)



We add all the numbers together, and all the variables

-(-1a+(6(2a+3)))*54+1=0

We move all terms containing a to the left, all other terms to the right

-(-1a+(6(2a+3)))*54=-1

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