1/5(1+4)=1/2(6-a)

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Solution for 1/5(1+4)=1/2(6-a) equation:



1/5(1+4)=1/2(6-a)
We move all terms to the left:
1/5(1+4)-(1/2(6-a))=0
Domain of the equation: 2(6-a))!=0
a∈R
We add all the numbers together, and all the variables
-(1/2(-1a+6))+1/55=0
We calculate fractions
()/(-110a)+(2a(-)/(-110a)=0
We calculate terms in parentheses: +(2a(-)/(-110a), so:
2a(-)/(-110a
We add all the numbers together, and all the variables
2a0/(-110a
We multiply all the terms by the denominator
2a0
We add all the numbers together, and all the variables
2a
Back to the equation:
+(2a)
We add all the numbers together, and all the variables
2a+()/(-110a)=0
We multiply all the terms by the denominator
2a*(-110a)+()=0
We add all the numbers together, and all the variables
2a*(-110a)=0
We multiply parentheses
-220a^2=0
a = -220; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-220)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{-440}=0$

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