1/5(10-5(x-2))=1/10(x+1)

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Solution for 1/5(10-5(x-2))=1/10(x+1) equation: 


x in (-oo:+oo)

(1/5)*(10-(5*(x-2))) = (1/10)*(x+1) // - (1/10)*(x+1)

(1/5)*(10-(5*(x-2)))-((1/10)*(x+1)) = 0

(1/5)*(10-5*(x-2))+(-1/10)*(x+1) = 0

1/5*(10-5*(x-2))-1/10*(x+1) = 0

1/5*(10-5*(x-2))-1/10*(x+1) = 0

39/10-11/10*x = 0

39/10-11/10*x = 0

39/10-11/10*x = 0 // - 39/10

-11/10*x = -39/10 // : -11/10

x = -39/10/(-11/10)

x = 39/11

x = 39/11

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