1/5(10a-20)-3a=4a-25

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Solution for 1/5(10a-20)-3a=4a-25 equation: 



1/5(10a-20)-3a=4a-25

We move all terms to the left:

1/5(10a-20)-3a-(4a-25)=0



Domain of the equation: 5(10a-20)!=0

a∈R



We add all the numbers together, and all the variables

-3a+1/5(10a-20)-(4a-25)=0

We get rid of parentheses

-3a+1/5(10a-20)-4a+25=0

We multiply all the terms by the denominator


-3a*5(10a-20)-4a*5(10a-20)+25*5(10a-20)+1=0

Wy multiply elements

-15a^2(1-20a^2(1+125a(1+1=0

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