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t in (-oo:+oo)
(1/5)*(10*t-15) = 2*t // - 2*t
(1/5)*(10*t-15)-(2*t) = 0
(1/5)*(10*t-15)-2*t = 0
1/5*(10*t-15)-2*t = 0
1/5*(10*t-15)-2*t = 0
-3 = 0
-3 = 0
t belongs to the empty set
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