1/5(10x+15)=19-2x

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Solution for 1/5(10x+15)=19-2x equation: 



1/5(10x+15)=19-2x

We move all terms to the left:

1/5(10x+15)-(19-2x)=0



Domain of the equation: 5(10x+15)!=0

x∈R



We add all the numbers together, and all the variables

1/5(10x+15)-(-2x+19)=0

We get rid of parentheses

1/5(10x+15)+2x-19=0

We multiply all the terms by the denominator


2x*5(10x+15)-19*5(10x+15)+1=0

Wy multiply elements

10x^2(1-95x(1+1=0

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