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1/5(10x+2)-2=2/5(6x-9)
We move all terms to the left:
1/5(10x+2)-2-(2/5(6x-9))=0
Domain of the equation: 5(10x+2)!=0
x∈R
Domain of the equation: 5(6x-9))!=0We calculate fractions
x∈R
(5x6/(5(10x+2)*5(6x-9)))+(-10x1/(5(10x+2)*5(6x-9)))-2=0
We calculate terms in parentheses: +(5x6/(5(10x+2)*5(6x-9))), so:
5x6/(5(10x+2)*5(6x-9))
We multiply all the terms by the denominator
5x6
We add all the numbers together, and all the variables
5x^6
We do not support expression: x^6
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