1/5(10x+30)=6x+7

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Solution for 1/5(10x+30)=6x+7 equation: 



1/5(10x+30)=6x+7

We move all terms to the left:

1/5(10x+30)-(6x+7)=0



Domain of the equation: 5(10x+30)!=0

x∈R



We get rid of parentheses

1/5(10x+30)-6x-7=0

We multiply all the terms by the denominator


-6x*5(10x+30)-7*5(10x+30)+1=0

Wy multiply elements

-30x^2(1-35x(1+1=0

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