1/5(10x-15)=1/4(8-4x)

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Solution for 1/5(10x-15)=1/4(8-4x) equation: 



1/5(10x-15)=1/4(8-4x)

We move all terms to the left:

1/5(10x-15)-(1/4(8-4x))=0



Domain of the equation: 5(10x-15)!=0

x∈R





Domain of the equation: 4(8-4x))!=0

x∈R



We add all the numbers together, and all the variables

1/5(10x-15)-(1/4(-4x+8))=0

We calculate fractions


(4x(-)/(5(10x-15)*4(-4x+8)))+(-5x1/(5(10x-15)*4(-4x+8)))=0



We calculate terms in parentheses: +(4x(-)/(5(10x-15)*4(-4x+8))), so:

4x(-)/(5(10x-15)*4(-4x+8))

We add all the numbers together, and all the variables

4x0/(5(10x-15)*4(-4x+8))

We multiply all the terms by the denominator


4x0

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-5x1/(5(10x-15)*4(-4x+8))), so:

-5x1/(5(10x-15)*4(-4x+8))

We multiply all the terms by the denominator


-5x1

We add all the numbers together, and all the variables

-5x

Back to the equation:

+(-5x)



We get rid of parentheses

4x-5x=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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