1/5(10x-20)=1/3(12x-6)

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Solution for 1/5(10x-20)=1/3(12x-6) equation:


x in (-oo:+oo)

(1/5)*(10*x-20) = (1/3)*(12*x-6) // - (1/3)*(12*x-6)

(1/5)*(10*x-20)-((1/3)*(12*x-6)) = 0

(1/5)*(10*x-20)+(-1/3)*(12*x-6) = 0

1/5*(10*x-20)-1/3*(12*x-6) = 0

1/5*(10*x-20)-1/3*(12*x-6) = 0

-2*x-2 = 0

-2*x-2 = 0

-2*x-2 = 0 // + 2

-2*x = 2 // : -2

x = 2/(-2)

x = -1

x = -1

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