1/5(10x-6)=4/10(12x+8)

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Solution for 1/5(10x-6)=4/10(12x+8) equation: 



1/5(10x-6)=4/10(12x+8)

We move all terms to the left:

1/5(10x-6)-(4/10(12x+8))=0



Domain of the equation: 5(10x-6)!=0

x∈R





Domain of the equation: 10(12x+8))!=0

x∈R



We calculate fractions


(10x1/(5(10x-6)*10(12x+8)))+(-20x1/(5(10x-6)*10(12x+8)))=0



We calculate terms in parentheses: +(10x1/(5(10x-6)*10(12x+8))), so:

10x1/(5(10x-6)*10(12x+8))

We multiply all the terms by the denominator


10x1

We add all the numbers together, and all the variables

10x

Back to the equation:

+(10x)





We calculate terms in parentheses: +(-20x1/(5(10x-6)*10(12x+8))), so:

-20x1/(5(10x-6)*10(12x+8))

We multiply all the terms by the denominator


-20x1

We add all the numbers together, and all the variables

-20x

Back to the equation:

+(-20x)



We get rid of parentheses

10x-20x=0

We add all the numbers together, and all the variables

-10x=0

x=0/-10

x=0

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