1/5(10y-2)=y+5

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Solution for 1/5(10y-2)=y+5 equation:



1/5(10y-2)=y+5
We move all terms to the left:
1/5(10y-2)-(y+5)=0
Domain of the equation: 5(10y-2)!=0
y∈R
We get rid of parentheses
1/5(10y-2)-y-5=0
We multiply all the terms by the denominator
-y*5(10y-2)-5*5(10y-2)+1=0
Wy multiply elements
-5y^2(1-25y(1+1=0

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