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1/5(12-8x)=4(-2x-6)
We move all terms to the left:
1/5(12-8x)-(4(-2x-6))=0
Domain of the equation: 5(12-8x)!=0We add all the numbers together, and all the variables
x∈R
1/5(-8x+12)-(4(-2x-6))=0
We multiply all the terms by the denominator
-((4(-2x-6)))*5(-8x+12)+1=0
We calculate terms in parentheses: -((4(-2x-6)))*5(-8x+12), so:We add all the numbers together, and all the variables
(4(-2x-6)))*5(-8x+12
We add all the numbers together, and all the variables
-8x+(4(-2x-6)))*5(+12
Back to the equation:
-(-8x+(4(-2x-6)))*5(+12)
-(-8x+(4(-2x-6)))*512+1=0
We move all terms containing x to the left, all other terms to the right
-(-8x+(4(-2x-6)))*512=-1
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